[FIELD NOTES / Σ] page=1
∑_{k=1}^{n} k = n(n+1)/2
∇²n = 0
∇²z = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
10α² + 3α + 3 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 12 6 ; 3 13 | = 138
6ψ² + 5ψ + 2 = 0
E = mc²
∂y/∂γ = 1y
e^{i\pi} + 1 = 0
det| 11 3 ; 7 12 | = 111
8α² + 9α + 0 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
d/dt [t^3] = 3t^2
λ = h/p
7x² + 1x + 2 = 0
\frac{5}{7} \sum_{i=1}^{n} i^{2}
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
d/dt [t^3] = 3t^2
2x² + 1x + 5 = 0
8z² + 9z + 3 = 0
10n² + 4n + 7 = 0
8γ² + 5γ + 5 = 0
∫₀^∞ e^(-α²) dα = √π / 2
∇²γ = 0
7α² + 4α + 7 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 11 1 ; 1 12 | = 131
F = ma
∫₀^∞ e^(-y²) dy = √π / 2
d/dγ [γ^12] = 12γ^11
\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1
1ω² + 5ω + 2 = 0
iħ ∂ψ/∂t = Ĥψ
2H₂ + O₂ → 2H₂O
N₂ + 3H₂ ⇌ 2NH₃
N₂ + 3H₂ ⇌ 2NH₃
det| 3 3 ; 7 4 | = -9
det| 5 5 ; 3 6 | = 15
det| 9 5 ; 5 10 | = 65
e^{i\pi} + 1 = 0
d/dψ [ψ^9] = 9ψ^8
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
4φ² + 3φ + 0 = 0
\frac{5}{1} \sum_{i=1}^{n} i^{2}
\oint_C \vec{F}\cdot d\vec{r} = 0
det| 10 7 ; 2 11 | = 96
∑_{k=1}^{n} k = n(n+1)/2
∂y/∂ω = 2y
Fe₂O₃ + 3CO → 2Fe + 3CO₂
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
6γ² + 3γ + 7 = 0
10n² + 5n + 6 = 0
N₂ + 3H₂ ⇌ 2NH₃
F = G m₁m₂ / r²
∫₀^∞ e^(-θ²) dθ = √π / 2
∂θ/∂z = 4θ
det| 8 4 ; 7 9 | = 44
det| 6 4 ; 4 7 | = 26
det| 12 1 ; 7 13 | = 149
det| 5 7 ; 2 6 | = 16
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
E = mc²
det| 9 9 ; 7 10 | = 27
5y² + 1y + 2 = 0
\frac{8}{8} \sum_{i=1}^{n} i^{2}
det| 7 5 ; 0 8 | = 56
iħ ∂ψ/∂t = Ĥψ
d/dα [α^12] = 12α^11
ΔS ≥ 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃
\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 8 4 ; 5 9 | = 52
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∇²ψ = 0
\frac{3}{8} \sum_{i=1}^{n} i^{2}
12t² + 6t + 1 = 0
8r² + 3r + 0 = 0
det| 10 2 ; 1 11 | = 108
E = mc²
∇ × E = −∂B/∂t
det| 4 3 ; 6 5 | = 2
9ψ² + 1ψ + 7 = 0
3r² + 8r + 2 = 0
6y² + 9y + 5 = 0
N₂ + 3H₂ ⇌ 2NH₃
CH₄ + 2O₂ → CO₂ + 2H₂O
∫₀^∞ e^(-γ²) dγ = √π / 2
E = mc²
det| 11 4 ; 0 12 | = 132
\binom{n}{k} = \frac{n!}{k!(n-k)!}
9φ² + 3φ + 6 = 0
det| 9 5 ; 7 10 | = 55
\lim_{n\to 0} \frac{\sin n}{n} = 1
e^{i\pi} + 1 = 0
d/dβ [β^6] = 6β^5
PV = nRT
ΔS ≥ 0
∇ × E = −∂B/∂t
2y² + 2y + 5 = 0
\oint_C \vec{F}\cdot d\vec{r} = 0