Field Notes / Σ /sym/3cad98
id=1 · host=formula-vault.cloud · 2026-10-20 00:11Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
446K
3x² + 3x + 6 = 0
det| 7 4 ; 4 8 | = 40
371K
∇²t = 0
7z² + 2z + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
218K
∑_{k=1}^{n} k = n(n+1)/2
354K