Field Notes / Σ /sym/3cad98
id=1 · host=formula-vault.cloud · 2026-10-20 00:54Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
168K
∫₀^∞ e^(-t²) dt = √π / 2
446K
3x² + 3x + 6 = 0
∇²t = 0
det| 9 4 ; 1 10 | = 86
86K
det| 9 5 ; 1 10 | = 85
224K
∑_{k=1}^{n} k = n(n+1)/2
234K