Field Notes / Σ /sym/3cad98
id=1 · host=formula-vault.cloud · 2026-10-20 00:20Z
∑_{k=1}^{n} k = n(n+1)/2
3x² + 3x + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
144K
∇²t = 0
det| 9 4 ; 1 10 | = 86
86K
7z² + 2z + 0 = 0
det| 9 8 ; 3 10 | = 66
224K
∑_{k=1}^{n} k = n(n+1)/2
234K
det| 4 2 ; 5 5 | = 10
∑_{k=1}^{n} k = n(n+1)/2
354K
2H₂ + O₂ → 2H₂O
iħ ∂ψ/∂t = Ĥψ