Field Notes / Σ /sym/3cad98
id=1 · host=formula-vault.cloud · 2026-10-18 23:23Z
d/dn [n^4] = 4n^3
∑_{k=1}^{n} k = n(n+1)/2
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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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\lim_{θ\to 0} \frac{\sin θ}{θ} = 1
iħ ∂ψ/∂t = Ĥψ
∑_{k=1}^{n} k = n(n+1)/2
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\frac{2}{4} \sum_{i=1}^{n} i^{2}
det| 5 3 ; 7 6 | = 9
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det| 5 7 ; 5 6 | = -5
det| 7 4 ; 4 8 | = 40
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