Field Notes / Σ /sym/3cad98
id=1 · host=formula-vault.cloud · 2026-10-20 00:04Z
∑_{k=1}^{n} k = n(n+1)/2
3x² + 3x + 6 = 0
d/dφ [φ^11] = 11φ^10
371K
∇²t = 0
∑_{k=1}^{n} k = n(n+1)/2
86K
7z² + 2z + 0 = 0
det| 9 4 ; 1 10 | = 86
224K
∑_{k=1}^{n} k = n(n+1)/2
218K
∑_{k=1}^{n} k = n(n+1)/2
354K