Field Notes / Σ /sym/3cad98
id=1 · host=formula-vault.cloud · 2026-10-20 00:55Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
168K
3x² + 3x + 6 = 0
det| 7 8 ; 4 8 | = 24
144K
∇²t = 0
7z² + 2z + 0 = 0
det| 7 4 ; 4 8 | = 40
234K
det| 4 2 ; 5 5 | = 10
det| 10 7 ; 3 11 | = 89
354K
∑_{k=1}^{n} k = n(n+1)/2
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