Field Notes / Σ /sym/3cad98
id=1 · host=formula-vault.cloud · 2026-10-18 22:57Z
∑_{k=1}^{n} k = n(n+1)/2
∫₀^∞ e^(-n²) dn = √π / 2
384K
det| 11 9 ; 4 12 | = 96
det| 7 4 ; 4 8 | = 40
163K
det| 10 3 ; 4 11 | = 98
259K
∇ × E = −∂B/∂t
det| 5 2 ; 3 6 | = 24
305K
det| 7 9 ; 1 8 | = 47
293K
∫₀^∞ e^(-t²) dt = √π / 2
34K
∑_{k=1}^{n} k = n(n+1)/2
354K