Field Notes / Σ /sym/3cad98
id=1 · host=formula-vault.cloud · 2026-10-19 07:39Z
∑_{k=1}^{n} k = n(n+1)/2
\frac{6}{1} \sum_{i=1}^{n} i^{2}
∂x/∂θ = 8x
det| 4 2 ; 6 5 | = 8
339K
3φ² + 4φ + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
358K
∑_{k=1}^{n} k = n(n+1)/2
11K