Field Notes / Σ /sym/3cad98
id=1 · host=formula-vault.cloud · 2026-10-19 07:41Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
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\frac{6}{1} \sum_{i=1}^{n} i^{2}
∂x/∂θ = 8x
3φ² + 4φ + 2 = 0
5ω² + 6ω + 0 = 0
det| 2 3 ; 5 3 | = -9
399K
∫₀^∞ e^(-θ²) dθ = √π / 2
∑_{k=1}^{n} k = n(n+1)/2
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