Field Notes / Σ /sym/3cad98
id=1 · host=formula-vault.cloud · 2026-10-19 07:35Z
∑_{k=1}^{n} k = n(n+1)/2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
468K
\frac{6}{1} \sum_{i=1}^{n} i^{2}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
289K
∂x/∂θ = 8x
\frac{4}{9} \sum_{i=1}^{n} i^{2}
177K
3φ² + 4φ + 2 = 0
det| 2 7 ; 7 3 | = -43
358K
∑_{k=1}^{n} k = n(n+1)/2
121K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
399K