Field Notes / Σ /sym/3cad98
id=1 · host=formula-vault.cloud · 2026-10-20 00:09Z
∑_{k=1}^{n} k = n(n+1)/2
3x² + 3x + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
144K
det| 7 7 ; 4 8 | = 28
371K
∇²t = 0
det| 1 4 ; 3 2 | = -10
259K
det| 7 4 ; 4 8 | = 40
86K
det| 5 9 ; 7 6 | = -33
234K
∑_{k=1}^{n} k = n(n+1)/2
218K
∑_{k=1}^{n} k = n(n+1)/2
70K