Field Notes / Σ /sym/3cad98
id=1 · host=formula-vault.cloud · 2026-10-18 23:42Z
d/dn [n^4] = 4n^3
\frac{12}{6} \sum_{i=1}^{n} i^{2}
384K
∑_{k=1}^{n} k = n(n+1)/2
385K
\lim_{θ\to 0} \frac{\sin θ}{θ} = 1
iħ ∂ψ/∂t = Ĥψ
det| 2 3 ; 5 3 | = -9
305K
\frac{2}{4} \sum_{i=1}^{n} i^{2}
det| 9 4 ; 1 10 | = 86
293K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
34K