Field Notes / Σ /sym/3cad98
id=1 · host=formula-vault.cloud · 2026-10-19 07:33Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
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det| 9 4 ; 1 10 | = 86
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\frac{6}{1} \sum_{i=1}^{n} i^{2}
∂x/∂θ = 8x
∑_{k=1}^{n} k = n(n+1)/2
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3φ² + 4φ + 2 = 0
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
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∫₀^∞ e^(-n²) dn = √π / 2
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∑_{k=1}^{n} k = n(n+1)/2
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