Field Notes / Σ /sym/3cad98
id=1 · host=formula-vault.cloud · 2026-10-20 00:05Z
∑_{k=1}^{n} k = n(n+1)/2
3x² + 3x + 6 = 0
Fe₂O₃ + 3CO → 2Fe + 3CO₂
371K
∇²t = 0
∑_{k=1}^{n} k = n(n+1)/2
259K
det| 7 4 ; 4 8 | = 40
86K
∫₀^∞ e^(-t²) dt = √π / 2
234K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
354K