Field Notes / Σ /sym/3cad98
id=1 · host=formula-vault.cloud · 2026-10-19 07:37Z
∑_{k=1}^{n} k = n(n+1)/2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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\frac{6}{1} \sum_{i=1}^{n} i^{2}
∫₀^∞ e^(-ω²) dω = √π / 2
289K
∂x/∂θ = 8x
3φ² + 4φ + 2 = 0
\frac{8}{6} \sum_{i=1}^{n} i^{2}
358K
\frac{4}{6} \sum_{i=1}^{n} i^{2}
121K
5ω² + 6ω + 0 = 0
\frac{12}{6} \sum_{i=1}^{n} i^{2}
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det| 9 4 ; 1 10 | = 86
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