Field Notes / Σ /sym/3cad98
id=1 · host=formula-vault.cloud · 2026-10-19 07:39Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
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\frac{6}{1} \sum_{i=1}^{n} i^{2}
det| 2 7 ; 7 3 | = -43
289K
det| 11 9 ; 0 12 | = 132
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∂x/∂θ = 8x
∫₀^∞ e^(-x²) dx = √π / 2
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3φ² + 4φ + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
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