Field Notes / Σ /sym/3cad98
id=1 · host=formula-vault.cloud · 2026-10-19 07:54Z
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
468K
\frac{6}{1} \sum_{i=1}^{n} i^{2}
∂x/∂θ = 8x
det| 12 6 ; 0 13 | = 156
339K
det| 6 6 ; 5 7 | = 12
177K
3φ² + 4φ + 2 = 0
5ω² + 6ω + 0 = 0
det| 7 4 ; 4 8 | = 40
399K
∑_{k=1}^{n} k = n(n+1)/2
387K