Field Notes / Σ /sym/3cad98
id=1 · host=formula-vault.cloud · 2026-10-20 03:51Z
∇ × E = −∂B/∂t
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
\binom{n}{k} = \frac{n!}{k!(n-k)!}
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∂x/∂n = 6x
∑_{k=1}^{n} k = n(n+1)/2
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\lim_{x\to 0} \frac{\sin x}{x} = 1
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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det| 12 1 ; 5 13 | = 151
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\binom{n}{k} = \frac{n!}{k!(n-k)!}
det| 9 4 ; 1 10 | = 86
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N₂ + 3H₂ ⇌ 2NH₃
d/dy [y^6] = 6y^5