Field Notes / Σ /sym/3cad98
id=1 · host=formula-vault.cloud · 2026-10-20 00:07Z
∑_{k=1}^{n} k = n(n+1)/2
3x² + 3x + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
144K
∇²t = 0
∑_{k=1}^{n} k = n(n+1)/2
259K
CH₄ + 2O₂ → CO₂ + 2H₂O
86K
7z² + 2z + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
224K
det| 2 7 ; 7 3 | = -43
234K
det| 7 4 ; 4 8 | = 40
218K