Field Notes / Σ /sym/3cad98
id=1 · host=formula-vault.cloud · 2026-10-20 00:18Z
∑_{k=1}^{n} k = n(n+1)/2
3x² + 3x + 6 = 0
∇²t = 0
∑_{k=1}^{n} k = n(n+1)/2
86K
det| 9 4 ; 1 10 | = 86
234K
det| 12 1 ; 5 13 | = 151
218K
∫₀^∞ e^(-t²) dt = √π / 2
354K
∑_{k=1}^{n} k = n(n+1)/2
70K
det| 2 7 ; 7 3 | = -43
402K